12Ycndtable


 * Cumulative Normal Distribution (CND) Table **

To find probabilities using the Standard Normal Distribution: Z ~ N( 0, 1 )


 * Example 1 (2 decimal places) **

Find Pr(Z < 0.43) Hence Pr(Z < 0.43) = 0.6664
 * 1) Go down the left column to find 0.4 (1st decimal place)
 * 2) Move across to find column labelled 3 (2nd decimal place)




 * Example 2 (3 decimal places) **

Find Pr(Z < 0.934) This gives Pr(Z < 0.93) = 0.8238 The appropriate mean difference is 10, so add 10 to the 4th decimal place of the value we got from step 2 (ie add 0.0010)
 * Go down the left column to find 0.9 (1st decimal place)
 * Move across to find column labelled 3 (2nd decimal place)
 * Then look up the mean difference(right section of table) for 4 (3rd decimal place)

Hence Pr(Z < 0.934) = 0.8248 .